Replies

  • Sahar September 14, 2011 11:49

    Solution:

     

    Let  y= f(x)

     

    y =√{1-√(x-1)} ≥0

     

    Then we have:

     

    y^2  =1-√(x-1)

    (y^2)-1 = -√(x-1)

    (y^2)-1 ≤ 0

     

    Then:

    y≥0      &     (y^2)-1 ≤ 0

     

    And the answer is [0,1]

  • This reply was deleted.
    • Sahar September 9, 2011 7:29

      Yes!!

      Well done!

      You are very clever.

      Always trust on yourself, please.

      They aren't hard questions, Sue, but you are answering all of them right.

      Very good.

    • Sahar September 9, 2011 4:51
      It means all of the ,1-√(x-1), are under the Radical.
This reply was deleted.