1-If we have:
[x] ≤ (x/2)
Then which one is right?
1- {x: x>1}
2- {x: x<1}
3- {x: -1<x<1}
4- {x: -2<x<0}
******* ******* ******* ******* *******
2-Which one is odd?
1- Ln {x+√(1+x2)}
2- e^sinx
3- (e^|x|)/(x+1)
4- sechx
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Replies
And also we can find it from their diagram:
A function is "even" when it is symmetry about the y-axis
A function is "odd" when we get origin symmetry.
http://www.mathsisfun.com/algebra/functions-odd-even.html
That's the sinh-1 curve.
http://www.ucl.ac.uk/Mathematics/geomath/level2/hyper/hy8b.html
Dear Zahra, we must consider their function, and we have:
f(x) is odd if we have:
f(-x) = - f(x)
And it is even if we have:
f(-x) = f(x)
** If f1 , f2 are even and g1 , g2 are odd and nonzero, and "a" , "b" be 2 real number and nonzero then we will have:
a g1 + bg2 = Odd
a f1 + bf2 = Even
a f1 + bg1= Not even and not odd
f1 f2 = g1g2 = Even
f1/ f2 = g1/g2 = Even
f1 g1 = f1/g1 = Odd
If f is an arbitrary function then f(f1) is always even.
W0W!!
Zahra!
You are a God in math!!
Very nice dear!
Very nice...
Well done!
I enjoyed reading your precise solution!
Very good, my dear.
Excellent!
Well done!
Excellent dear!!
That's right.